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I don't know the details of the attack, but the article says, "AES-128 is more like AES-126", so you should therefore need 2^125 operations in average, which is 4 times faster.

On the other hand, I may be wrong... do you mind linking to the original source?



dchest linked below. Their attack on AES-128 is claimed to be 2^126.1 operations.




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